# Question #66675

Apr 16, 2017

$f \left(x\right) = g \left(- x - 1\right)$ which is answer B.

#### Explanation:

The slope-intercept form of a line is $y = m x + b$, where $m = \frac{\Delta y}{\Delta x}$ and $b$ is the $y$-intercept $\left(0 , b\right)$

This means that $f \left(x\right) = 3 x + 4 \text{ and } g \left(x\right) = - 3 x + 1$

$g \left(- x\right) = - 3 \left(- x\right) + 1 = 3 x + 1$

$f \left(x\right) \ne g \left(- x\right) - 3$

$g \left(- x - 1\right) = - 3 \left(- x - 1\right) + 1 = 3 x + 3 + 1 = 3 x + 4$

$f \left(x\right) = g \left(- x - 1\right)$ which is answer B.