# A gas is placed in a piston whose volume was 19.7*L under a pressure of 0.95*atm. If the volume were reduced to 22.5*L, what resultant pressure would develop?

Dec 19, 2016

The pressure of the system is 0.83 atm

#### Explanation:

To find the final pressure of the system we can use Boyle's Law:

Based on the information you've given me, we know the following variables:

${P}_{1}$ = 0.95 atm
${V}_{1}$ = 19.7 L
${V}_{2}$ = 22.5 L
${P}_{2}$ = $x$

Since we don't know what ${P}_{2}$ is, the equation has to be rearranged by dividing both sides by ${V}_{2}$ to get ${P}_{2}$ by itself:

${P}_{2} = \frac{{P}_{1} \times {V}_{1}}{V} _ 2$

Now, just plug the given values into the equation:

${P}_{2} = \frac{0.95 a t m \times 19.7 \cancel{L}}{22.5 \cancel{L}}$

${P}_{2}$ = 0.83 atm