A gas is placed in a piston whose volume was #19.7*L# under a pressure of #0.95*atm#. If the volume were reduced to #22.5*L#, what resultant pressure would develop?

1 Answer
Dec 19, 2016

Answer:

The pressure of the system is 0.83 atm

Explanation:

To find the final pressure of the system we can use Boyle's Law:
http://slideplayer.com/slide/5281881/

Based on the information you've given me, we know the following variables:

#P_1# = 0.95 atm
#V_1# = 19.7 L
#V_2# = 22.5 L
#P_2# = #x#

Since we don't know what #P_2# is, the equation has to be rearranged by dividing both sides by #V_2# to get #P_2# by itself:

#P_2 = (P_1xxV_1)/V_2#

Now, just plug the given values into the equation:

#P_2 = (0.95 atm xx19.7cancelL)/(22.5cancelL)#

#P_2# = 0.83 atm