# Question #bded0

Nov 21, 2016

We use Boyle's law, ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$...........${P}_{1} = 3.60 \times {10}^{-} 2 \cdot c m \cdot H g$

#### Explanation:

We use Boyle's law, ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$, and solve for ${P}_{1}$.

${P}_{1} = \frac{{P}_{2} {V}_{2}}{V} _ 1 = \frac{30.0 \cdot m m \cdot H g \times 0.240 \cdot c {m}^{3}}{200 \cdot c {m}^{3}}$

$= 0.360 \cdot m m \cdot H g$