# Question #d48c4

Nov 15, 2016

We can simplify to $2 \sqrt[3]{9} + 4 \sqrt[3]{3}$.

#### Explanation:

Start by simplifying everything as much as you can. Remember you are dealing with cube roots.

$\implies 4 \sqrt[3]{9} - 5 \sqrt[3]{3} - \sqrt[3]{8 \times 9} + 3 \sqrt[3]{27 \times 3}$

$\implies 4 \sqrt[3]{9} - 5 \sqrt[3]{3} - 2 \sqrt[3]{9} + 3 \left(3\right) \sqrt[3]{3}$

$\implies 4 \sqrt[3]{9} - 5 \sqrt[3]{3} - 2 \sqrt[3]{9} + 9 \sqrt[3]{3}$

$\implies 2 \sqrt[3]{9} + 4 \sqrt[3]{3}$

We're done here, because everything is irreducible.

Hopefully this helps!