# Question fcec8

Nov 25, 2016

$C a O \left(s\right) + 2 H N {O}_{3} \left(a q\right) \rightarrow C a {\left(N {O}_{3}\right)}_{2} \left(a q\right) + {H}_{2} O \left(l\right)$

#### Explanation:

$\text{Moles of calcium oxide}$ $=$ (1.5*g)/(56.08*g*mol^-1)=??*"moles".

I think your original question would have asked you the concentration of the solution with respect to calcium; and maybe its $p H$ if an initial volume were specified.

$\text{Concentration}$ $=$ $\frac{1.5 \cdot g}{56.08 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{\text{Volume (L)}}$ $=$ ??*mol*L^-1.

pH=-log_10{2xx(1.5*g)/(56.08*g*mol^-1)xx1/("Volume (L)")}=??#

Note that $\text{calcium oxide}$ dissolves in water according to the following reaction:

$C a O \left(s\right) + {H}_{2} O \left(l\right) \rightarrow C a {\left(O H\right)}_{2} \left(a q\right)$