# Question #64952

##### 1 Answer

#### Explanation:

The key to any dilution calculation is the fact that the amount of *solute* remains **unchanged**. The only thing that changes when a solution is diluted is the amount of *solvent*.

Now, an **for every**

#175 color(red)(cancel(color(black)("mL solution"))) * "11 g solute"/(100color(red)(cancel(color(black)("mL solution")))) = "19.25 g solute"#

This is **exactly** how much solute will be present in your diluted solution. You dilute the initial solution by adding water, which is your solvent.

To find the mass by volume percent concentration of the diluted solution, use the fact that it contains

Your goal here is to figure out how much solute will the diluted solution contain in

#100 color(red)(cancel(color(black)("mL solution"))) * "19.25 g solute"/(750color(red)(cancel(color(black)("mL solution")))) = "2.6 g solute"#

Therefore, you can say that the diluted solution has a mass by volume percent concentration of

#color(darkgreen)(ul(color(black)("% m/v" = 2.6%)))#

The answer is rounded to two **sig figs**.