# What mass of sodium hydroxide is required for a 1*L volume of 3*mol*L^-1 sodium hydroxide solution?

Nov 28, 2016

You need an approx. $120 \cdot g$ mass.

#### Explanation:

$\text{Concentration"="Moles of solute"/"Volume of solution (L)}$,

and thus:

$\text{mass of solute"="concentration"xx"volume"xx"molar mass NaOH}$.

Given that $\text{Concentration} = 3 \cdot m o l \cdot {L}^{-} 1$, in a $1 \cdot L$ volume, there are 3*mol*L^-1xx1*Lxx40.0*g*mol^-1=??g $\text{NaOH}$.

What is the $p H$ of this solution?