Question

Question #0b46c

Answer 1

Here's how I would do it.

Step 1. Draw a 10-carbon (decane) chain.

`"decane"`

Step 2. Number the carbons from left to right.

Attach an isopropyl group to carbon 4.

`"4-isopropyldecane"`

Step 3. Attach a sec-butyl group to carbon 5.

`"4-isopropyl-5-sec-butyldecane"`

And you have the structure.