How many moles of #"iron(Ill) sulfide"#, #Fe_2S_3#, would be produced from the complete reaction of #449*g# #"iron(III) bromide"# in the reaction #2FeBr_3 + 3Na_2S -> Fe_2S_3 + 6NaBr#?
1 Answer
Aug 15, 2017
The stoichiometric equation specifies half an equiv of ferric sulfide with respect to ferric bromide.
Explanation:
And thus we simply calculate the moles of ferric bromide.
And thus we gets an half equiv of the sulfide salt....which represents a mass of....