# What is the resultant concentration when a 30*mL of a 2.0*mol*L^-1 are diluted to a new volume of 150*mL?

Dec 8, 2016

$\text{Concentration"="Moles of solute"/"Volume of solution}$

#### Explanation:

And we simply have to work the quotient:

(30xx10^-3*Lxx2.0*mol*L^-1)/(150xx10^-3L)=??mol*L^-1.

This is dimensionally consistent; $\left(30 \cdot m L \times 2.0 \cdot m o l \cdot {L}^{-} 1\right) = \left(30 \times {10}^{-} 3 L \times 2.0 \cdot m o l \cdot {L}^{-} 1\right)$ gives me an answer in $m o l$. And, the quotient gives me an answer in $m o l \cdot {L}^{-} 1$.

Happy?