Question

Question #94789

Answer 1

y varies directly as x and inversely as the square of z.

So `ypropx/z^2`

`=>y=kx/z^2," where k is variation constant"`

Given `y=4 " when "x=50 and z=5`

So `4=k*50/5^2=>k=2`

Hence `y=2*x/z^2`

Now when `x=56 and z=2`, y becomes
`y=2*56/2^2=28`