How do you prove the identity #(sin^3x - cos^3x)/(sinx - cosx) =1 + sinxcosx#?
2 Answers
Dec 20, 2016
Start by factoring
So,
#(sin^3x - cos^3x)/(sinx - cosx) = 1 + sinxcosx#
The
#sin^2x + sinxcosx + cos^2x = 1 + sinxcosx#
Use the identity
#1 + sinxcosx = 1 + sinxcosx#
#LHS = RHS#
Hopefully this helps!
Dec 20, 2016
See below.
Explanation:
From the polynomial identity