# Question #f22bd

Jan 7, 2017

Electrons transfer to the more electronegative atom in this case, but both ions formed have noble gas configuration.

#### Explanation:

In an ionic compound, the more electronegative atom will gain the electron from the less electronegative atom, but as a result, both ions formed will have the noble gas electron configuration.

Here is an example:

sodium, Na: $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{1}$

chlorine, Cl: $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{5}$

After transfer of an electron to the more electronegative Cl, two ions result:

sodium, $N {a}^{+}$: $1 {s}^{2} 2 {s}^{2} 2 {p}^{6}$

chloride, $C {l}^{-}$: $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6}$

Both ions have ${s}^{2} {p}^{6}$ outer electrons.