# Question #91c74

Jan 5, 2018

This is one of $S {O}_{2}$'s major resonance forms,

where we assume that the sulfur atom has one lone pair of electrons.

And this is $S {O}_{3}$'s Lewis structure,

where sulfur has an expanded octet due to its more broad range of orbitals.

Notice that each central sulfur atom has three substituents in its orbitals: $S {O}_{2}$ two oxygen atoms and a lone pair, and $S {O}_{3}$ three oxygen atoms.

Hence, each sulfur atom's orbitals hybridize into three ${\text{sp}}^{2}$ and one $\text{p}$ orbital remains.