# Question #0ed52

##### 1 Answer

The answer assumes that

for part (a) charge

For part (b) potential difference

We know that Capacitance

#C-=Q/V#

where#Q =# magnitude of charge stored on each plate of the capacitor, and#V =# voltage applied to the plates. Its SI units are Farad#F#

(a) When charge is doubled. Assuming that there is no change in the applied voltage, as shown from the equation above, capacitance is doubled;

(b) When the potential difference