Question #117c1

1 Answer
Matt
Feb 16, 2017

It would be less than that of air.

Explanation:

The wavelength of each harmonic is a function of the tube length so independent of the gas used. The speed of a wave is given by:

#c=flamda#

Since #lamda# for the harmonic is the same as air (independent of the gas), then since the speed (#c#), is lower in #CO_2#, the frequency (#f#) must also be lower for each harmonic.

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