# How do you solve: 3 >= 3x + 6?

Feb 20, 2017

See the entire solution process below:

#### Explanation:

Step 1) Subtract $\textcolor{red}{6}$ from each side of the inequality to isolate the $x$ term while keeping the inequality balanced:

$3 - \textcolor{red}{6} \ge 3 x + 6 - \textcolor{red}{6}$

$- 3 \ge 3 x + 0$

$- 3 \ge 3 x$

Step 2) Divide each side of the inequality by $\textcolor{red}{3}$ to solve for $x$ while keeping the inequality balanced:

$- \frac{3}{\textcolor{red}{3}} \ge \frac{3 x}{\textcolor{red}{3}}$

$- 1 \ge \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} x}{\cancel{\textcolor{red}{3}}}$

$- 1 \ge x$

To solve in terms of $x$ we must reverse or "flip" the inequality"

$x \le - 1$