# Question #5b7cb

##### 1 Answer

Jan 25, 2017

#### Answer:

#### Explanation:

We know that in such interactions heat is gained by one and heat is lost is by the other.

Also that the heat gained/lost is given by

#DeltaQ=mst# ,

where#m,s and t# are the mass, specific heat and rise or gain in temperature of the object;

and

#Delta Q_"lost"=Delta Q_"gained"#

Let

Heat gained by water

Equating (1) and (2) we get

Multiplying both sides by