Question #008eb

1 Answer
Feb 1, 2017

Answer:

Choices a, b, and d are not written properly
and,
there is nothing wrong with choice c

Explanation:

Choice a, b, and d are all not correct valence electron configurations when writing the valence electron shorthand.

Choice a is incorrect because for #n=2, l=0# there are only two orbital about the (#s#) subshell.

Choice b is incorrect because two "#2s^2#" orbital are written and the next two electron would instead fill the #n=2,l=1# (#p#) shell and its 3 orbital.

Choice d is incorrect because for #n=1#, #l# can only #=0#. Remember that #l# can have value between #0 -> n-1#.

In other words, there is no such thing as a "#1p#" orbital.