# Question #008eb

##### 1 Answer
Feb 1, 2017

Choices a, b, and d are not written properly
and,
there is nothing wrong with choice c

#### Explanation:

Choice a, b, and d are all not correct valence electron configurations when writing the valence electron shorthand.

Choice a is incorrect because for $n = 2 , l = 0$ there are only two orbital about the ($s$) subshell.

Choice b is incorrect because two "$2 {s}^{2}$" orbital are written and the next two electron would instead fill the $n = 2 , l = 1$ ($p$) shell and its 3 orbital.

Choice d is incorrect because for $n = 1$, $l$ can only $= 0$. Remember that $l$ can have value between $0 \to n - 1$.

In other words, there is no such thing as a "$1 p$" orbital.