# Question 5b8b4

Feb 6, 2017

The $y$ intercept of both lines is $- 1$.

#### Explanation:

First, you'll want to convert the equations to standard form, which is

$y = m x + b$

Then, $b$ will be the $y$ intercept.

$16 x - 10 y = 10 \implies 10 y = 16 x - 10 \implies y = \frac{16}{10} x - 1$

$- 1$ is the $y$ intercept here, and the point is $\left(0 , - 1\right)$.

Here is a graph of $16 x - 10 y = 10$:

graph{16x-10y=10 [-10, 10, -5, 5]}

$- 8 x - 6 y = 6 \implies 6 y = - 8 x - 6 \implies y = - \frac{8}{6} x - 1$

$- 1$ is the $y$ intercept again, and the point is $\left(0 , - 1\right)$.

Here is a graph of $- 8 x - 6 y = 6$:

graph{-8x-6y=6 [-10, 10, -5, 5]}

Feb 6, 2017

$\text{y-intercept "=-1" for both equations}$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{slope-intercept form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = m x + b} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where m represents the slope and b, the y-intercept.

$\text{for } 16 x - 10 y = 10$

Rearrange into this form to obtain y-intercept.

subtract 16x from both sides of the equation.

$\cancel{16 x} \cancel{- 16 x} - 10 y = 10 - 16 x = - 16 x + 10$

$\Rightarrow - 10 y = - 16 x + 10$

divide ALL terms on both sides by - 10

(cancel(-10) y)/cancel(-10)=(-16)/(-10)x+10/(-10#

$\Rightarrow y = \frac{8}{5} x - 1 \leftarrow \textcolor{red}{\text{ in form y = mx + b}}$

$\Rightarrow b = - 1 = \text{ y-intercept}$

Repeat the process for $- 8 x - 6 y = 6$

to obtain $y = - \frac{4}{3} x - 1 \Rightarrow \text{ y-intercept } = - 1$