# Question #5b8b4

##### 2 Answers

#### Answer:

The

#### Explanation:

First, you'll want to convert the equations to standard form, which is

Then,

Here is a graph of

graph{16x-10y=10 [-10, 10, -5, 5]}

Here is a graph of

graph{-8x-6y=6 [-10, 10, -5, 5]}

#### Answer:

#### Explanation:

The equation of a line in

#color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#

where m represents the slope and b, the y-intercept.

#"for " 16x-10y=10# Rearrange into this form to obtain y-intercept.

subtract 16x from both sides of the equation.

#cancel(16x)cancel(-16x)-10y=10-16x=-16x+10#

#rArr-10y=-16x+10# divide ALL terms on both sides by - 10

#(cancel(-10) y)/cancel(-10)=(-16)/(-10)x+10/(-10#

#rArry=8/5x-1larrcolor(red)" in form y = mx + b"#

#rArrb=-1=" y-intercept"# Repeat the process for

#-8x-6y=6# to obtain

#y=-4/3x-1rArr" y-intercept "=-1#