Question #5b8b4

2 Answers
Feb 6, 2017

Answer:

The #y# intercept of both lines is #-1#.

Explanation:

First, you'll want to convert the equations to standard form, which is

#y = mx + b#

Then, #b# will be the #y# intercept.

#16x - 10y = 10 => 10y = 16x - 10 => y = 16/10x - 1#

#-1# is the #y# intercept here, and the point is #(0,-1)#.

Here is a graph of #16x - 10y = 10#:

graph{16x-10y=10 [-10, 10, -5, 5]}

#-8x -6y = 6 => 6y = -8x -6 => y = -8/6x -1#

#-1# is the #y# intercept again, and the point is #(0,-1)#.

Here is a graph of #-8x-6y = 6#:

graph{-8x-6y=6 [-10, 10, -5, 5]}

Feb 6, 2017

Answer:

#"y-intercept "=-1" for both equations"#

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

#"for " 16x-10y=10#

Rearrange into this form to obtain y-intercept.

subtract 16x from both sides of the equation.

#cancel(16x)cancel(-16x)-10y=10-16x=-16x+10#

#rArr-10y=-16x+10#

divide ALL terms on both sides by - 10

#(cancel(-10) y)/cancel(-10)=(-16)/(-10)x+10/(-10#

#rArry=8/5x-1larrcolor(red)" in form y = mx + b"#

#rArrb=-1=" y-intercept"#

Repeat the process for #-8x-6y=6#

to obtain #y=-4/3x-1rArr" y-intercept "=-1#