# Question #eda6e

##### 1 Answer

Dec 27, 2017

#### Explanation:

#"eliminate the fractions by multiplying ALL terms by"#

#"12 the lowest common multiple of 3 and 4"#

#cancel(12)^4xx1/cancel(4)^1(y+4)+84=cancel(12)^3(3y-2)-24#

#rArr4(y+4)+84=3(2y-2)-24#

#"distribute brackets on both sides and collect like terms"#

#rArr4y+16+84=9y-6-24#

#rArr4y+100=9y-30#

#"subtract 9y from both sides"#

#4y-9y+100=cancel(9y)cancel(-6y)-30#

#rArr-5y+100=-30#

#"subtract 100 from both sides"#

#-5ycancel(+100)cancel(-100)=-30-100#

#rArr-5y=-130#

#"divide both sides by "-5#

#(cancel(-5) y)/cancel(-5)=(-130)/(-5)#

#rArry=26#

#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=1/3(30)+7=10+7=17#

#"right "=1/4(76)-2=19-2=17#

#rArry=26" is the solution"#