What is the amplitude, period and phase shift for #y = 4cos(pix)#?

1 Answer
Feb 24, 2018

Amplitude

This is described by the a parameter, or the number directly to the left of the sine or cos, in this case #4#.

Period

The period is given by #(2pi)/b#, where #y = acos(b(x - c)) + d#.

Thus the period is

#(2pi)/pi = 2#

Phase Shift

There is no phase shift because #c = 0#.

Hopefully this helps!