Question #fae95

1 Answer
Feb 13, 2017

1040g

Explanation:

The balanced equation for the combustion of octane is:
2C_8H_18 + 25O_2 -> 16CO_2 + 18H_2O

Therefore,
a. Calculate the number of moles of octane:
235g * "1mol"/"114.26g" = 2.96mol

b. Calculate the grams of carbon dioxide:
2.96 "mol octane" * (16 "mol CO2")/(2 "mol octane") * (44.01g CO2)/(1 mol CO2) = 1042g

(To the appropriate number of sig figs: 1040g).