Question #848b4

1 Answer
Feb 21, 2017

Answer:

The charge moved through the circuit is 4290#C#oulombs.

Explanation:

When there is a transfer of charge from one side of an area to the other, we say that there is an electric current through the area.
If a charge #'DeltaQ'# crosses an area in time #'Deltat'#, we define the average electric current through the area during the time as
#bari=(DeltaQ)/(Deltat)#.
Simply,
#i=Q/t or i=q//t#.
Here time taken by current to flow through the circuit as 13 minutes.
We have to change this seconds, because Ampere=Coulombs/seconds.
#:. t=780 ##s#econds.

Substituting the numericals in the above equation we get,
#rArrq=i.t=5.5Axx780s=4290C#oulombs.