# Question #848b4

Feb 21, 2017

The charge moved through the circuit is 4290$C$oulombs.

#### Explanation:

When there is a transfer of charge from one side of an area to the other, we say that there is an electric current through the area.
If a charge $' \Delta Q '$ crosses an area in time $' \Delta t '$, we define the average electric current through the area during the time as
$\overline{i} = \frac{\Delta Q}{\Delta t}$.
Simply,
$i = \frac{Q}{t} \mathmr{and} i = q / t$.
Here time taken by current to flow through the circuit as 13 minutes.
We have to change this seconds, because Ampere=Coulombs/seconds.
$\therefore t = 780$$s$econds.

Substituting the numericals in the above equation we get,
$\Rightarrow q = i . t = 5.5 A \times 780 s = 4290 C$oulombs.