In this case, the set of like terms are #3/5x# and #7/8x#. To combine them, let's subtract #3/5x# from both sides. On the left side, the positive and negative #3/5x# cancel each other out or become equal to #0#.

#3/5x -(3/5x + 33 = 7/8x)- 3/5x#

So this is how our solution looks like.

#33 = 7/8x - 3/5x#

Let's focus on those two fractions. We'll be subtracting dissimilar fractions. First, we find the LCD (Least Common Denominator) of #8# and #5#, which is #40#.

#7/8x - 3/5x = -/40#

Next, we divide #40# by #8# and #5#. Then, the quotient of #40# and #8# is #5# and will be multiplied to #7#. The quotient of #40# and #5# is #8# and will be multiplied by #3#. The solution looks like this:

#7/8x - 3/5x = (35-24)/40#

Subtract 35 and 24 to get the following:

#33 = 11/40x#

Now let's isolate the variable #x#. We could apply cross-multiplication by multiplying #33# by #40#, #11# by #1# (which is underneath #33# this whole time). Solution becomes like this:

#33/1 = 11/40x# ==> #1320 = 11x#

DIvide both sides by #11# to get #x = 120#.

#1320/11 = 11/11x# ==> #120 = x#