# Question #f8908

Feb 15, 2017

Number of molecules $= 6.022 \cdot {10}^{22}$

#### Explanation:

The equation of the combustion is

$C + {O}_{2} \to C {O}_{2}$

If we had $12 g$ of $C$, the number of molecules liberated is

$= {N}_{A} = 6.022 \cdot {10}^{23}$ molecules

But, we have $\text{0.1 g atom = 1.2 g}$

So,

the number of molecules of $C {O}_{2}$

$= \frac{6.022 \cdot {10}^{23}}{12} \cdot 1.2$

$= 6.022 \cdot {10}^{22}$ molecules