# Do highly electronegative atoms form covalent bonds?

##### 1 Answer
Feb 24, 2017

Many elements of high electronegativity will form covalent bonds.....

#### Explanation:

And I can name three without thinking:

$\text{fluorine; oxygen; and nitrogen}$, which are of course the binuclear molecules ${X}_{2}$, $O = O$, and $N \equiv N$.

Electronegativity is conceived to be ability of an atom involved in a chemical bond to polarize electron density towards itself, resulting in a polar bond, where electron density is UNEQUALLY shared. For homonuclear diatomic molecules, given that the elements have EQUAL electronegativity, there should be no charge separation, no polarity in the $\text{element"-"element}$ bond.

On the other hand for $O {F}_{2}$, which is an isolable molecule, the dipole may be described as ""^(+delta)OF_2^(delta-). Why?