Question #c4774

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Answer 1 · 2017-03-02T17:29:03

For violet #sf(theta=41^@)#

For blue #sf(theta=48.8^@)#

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For constructive interference to occur, the path difference must be an integral number of wavelengths.

This is AC on the diagram.

#:.##sf(sintheta=(nlambda)/d)#

There are 800 lines in 1 mm.

#:.##sf(d=1/800=1.25xx10^(-3)color(white)(x)"mm")#

#sf(d=1.25xx10^(-6)color(white)(x)"m")#

For violet light when #sf(n=2)#:

#sf(sintheta=(2xx410xx10^(-9))/(1.25xx10^(-6))=0.656)#

#sf(theta=41^@)#

For blue light when #sf(n=2)#:

#sf(sintheta=(2xx470xx10^(-9))/(1.25xx10^(-6))=0.752)#

#sf(theta=48.8^@)#