Question #8e971

1 Answer
Mar 9, 2017

Balanced equation
C2H4 + H2O → C2H5OH
1mol C2H4 reacts with 1mol H2O to produce 1mol C2H5OH

How many grams of ethylene are needed to react with 0.130 mol of H2O? I got 3.65g
0.130mol H2O will react with 0.130mol C2H4
Molar mass C2H4 = 28.05 g/mol
0.130mol = 0.130*28.05 = 3.65g Your answer correct

How many grams of ethyl alcohol will result?
0.130mol ethanol will be produced
Molar mass C2H5OH = 46.07
0.130mol = 0.130*46.07 = 6.0g

How many grams of water are needed to react with 0.361 of ethylene? 6.51g
presume 0.361 mol.
0.361mol required = 0.361*18.0153 = 6.50g Your answer correct

How many grams of ethyl alcohol will result?
0.361mol C2H54OH will be produced
0.361mol = 0.361*46.07 = 16.63g C2H5OH will be produced.