Find the equation of a line having a slope of #1/3# and passing through point #(1,-2)#?

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Answer 1 · 2017-03-11T11:13:55

#x-3y-7=0#

Equation of a line having a slope of #m# and passing through point #(x_1,y_1)# is #y-y_1=m(x-x_1)#.

Hence, equation of a line having a slope of #1/3# and passing through point #(1,-2)# is

#y-(-2)=1/3(x-1)#

i.e. #y+2=1/3(x-1)#

or #3y+6=x-1#

and in general form i.e. #ax+by+c=0#,

desired equation is #x-3y-7=0#