# Find the equation of a line having a slope of 1/3 and passing through point (1,-2)?

Mar 11, 2017

$x - 3 y - 7 = 0$

#### Explanation:

Equation of a line having a slope of $m$ and passing through point $\left({x}_{1} , {y}_{1}\right)$ is $y - {y}_{1} = m \left(x - {x}_{1}\right)$.

Hence, equation of a line having a slope of $\frac{1}{3}$ and passing through point $\left(1 , - 2\right)$ is

$y - \left(- 2\right) = \frac{1}{3} \left(x - 1\right)$

i.e. $y + 2 = \frac{1}{3} \left(x - 1\right)$

or $3 y + 6 = x - 1$

and in general form i.e. $a x + b y + c = 0$,

desired equation is $x - 3 y - 7 = 0$