Question

`2LiOH(s)+CO_2(g) rarr Li_2CO_3(s) + H_2O(l)` What mass of carbon dioxide can be absorbed by a `1.30*kg` mass of lithium hydroxide, given the equation....?

Answer 1

Approx. `1200*g`.

Explanation:

You have given the stoichiometric equation:

`2LiOH(s)+CO_2(g) rarr Li_2CO_3(s) + H_2O(l)`.

And this unequivocally tells us that each mole of carbon dioxide required 2 moles of lithium hydroxide:

`"Moles of LiOH"=(1.3xx10^3*g)/(23.95*g*mol^-1)=54.3*mol`

And thus `27.1*mol` `CO_2` can be absorbed:

`27.1xx44.01*g*mol^-1~=1.2*kg`