# 2LiOH(s)+CO_2(g) rarr Li_2CO_3(s) + H_2O(l) What mass of carbon dioxide can be absorbed by a 1.30*kg mass of lithium hydroxide, given the equation....?

Mar 13, 2017

Approx. $1200 \cdot g$.

#### Explanation:

You have given the stoichiometric equation:

$2 L i O H \left(s\right) + C {O}_{2} \left(g\right) \rightarrow L {i}_{2} C {O}_{3} \left(s\right) + {H}_{2} O \left(l\right)$.

And this unequivocally tells us that each mole of carbon dioxide required 2 moles of lithium hydroxide:

$\text{Moles of LiOH} = \frac{1.3 \times {10}^{3} \cdot g}{23.95 \cdot g \cdot m o {l}^{-} 1} = 54.3 \cdot m o l$

And thus $27.1 \cdot m o l$ $C {O}_{2}$ can be absorbed:

$27.1 \times 44.01 \cdot g \cdot m o {l}^{-} 1 \cong 1.2 \cdot k g$