# Question 2603d

Mar 20, 2017

The gas reached a pressure of 2.5 atm.

Since the volume is constant but the pressure and temperature are changing, this is an example of Gay-Lussac's Law:

$\textcolor{b l u e}{\overline{\underline{| \textcolor{w h i t e}{\frac{a}{a}} {P}_{1} / {T}_{1} = {P}_{2} / {T}_{2} \textcolor{w h i t e}{\frac{a}{a}} |}}} \text{ }$

We can rearrange the above formula to get

P_2=P_1 × T_2/T_1#

${P}_{1} = \text{1 atm}$
${T}_{1} = \text{(20 + 273.15) K"color(white)(l) = "293.15 K}$
${P}_{2} = \text{?}$
${T}_{2} = \text{(473 + 273.15) K" = "746.15 K}$
${P}_{2} = \text{1 atm" × (746.15 color(red)(cancel(color(black)("K"))))/(293.15 color(red)(cancel(color(black)("K")))) = "2.5 atm}$