Question

Question #cc120

Answer 1

`1/5`

Explanation:

given `sin^2A+cos^2B`

draw a triangle as per given information.
from triangle,
`tanA=`(perpendicular)/(base)`= 1/2 rArrsinA=`(perpendicular)/(hypotenuse)#1/sqrt(1^2+2^2)=1/sqrt5 #
now,
`sin^2A+cos^2B`
`rArr(1/sqrt5)^2+(Cos(pi/2))^2 = 1/5 +0=1/5`