# Solve? 1/5+1/2=4(4/(5x-5))

$x = \frac{195}{35} = \frac{39 \times 5}{7 \times 5} = \frac{39}{7}$

#### Explanation:

$\frac{1}{5} + \frac{1}{2} = 4 \left(\frac{4}{5 x - 5}\right)$

I'll first combine the left hand side and multiply through on the right hand side:

$\frac{1}{5} \left(\frac{2}{2}\right) + \frac{1}{2} \left(\frac{5}{5}\right) = 4 \left(\frac{4}{5 x - 5}\right)$

$\frac{2}{10} + \frac{5}{10} = \frac{16}{5 x - 5}$

$\frac{7}{10} = \frac{16}{5 x - 5}$

Let's now cross multiply:

$7 \left(5 x - 5\right) = 10 \times 16$

$35 x - 35 = 160$

$35 x = 195$

$x = \frac{195}{35} = \frac{39 \times 5}{7 \times 5} = \frac{39}{7}$