Question

Question #b7afd

Answer 1

The additional mass is `=0.389kg`

Explanation:

The period of oscillation of a spring is given by

`T=2pisqrt(m/k)`

The peroid is `T=1.5s`

The mass is `m=0.500kg`

and `k` is the spring constant

Therefore,

`m/k=T^2/(4pi^2)`

`k=(4pi^2)/T^2*m`

`k=(4pi^2)/(1.5^2)*0.5`

The new peroid is

`T_1=2pisqrt(M/k)`

`2=2pisqrt(M/((4pi^2)/(1.5^2)*0.5))`

`1=pi^2*M/((4pi^2)/(1.5^2)*0.5)`

`M=4*0.5/(1.5^2)`

`M=2/1.5^5=0.889kg`

The additional mass is

`=0.889-0.500=0.389kg`