Question

If the period of an oscillatory motion is 2.4 seconds, what is the angular speed in rad/s and in degrees/s?

Answer 1

`0.833pi"rad/s"`

`150"deg/s"`

Explanation:

There are `2pi` radians in a circle.

The time period is the time taken to sweep `2pi` radians.

So `2pi` radians are swept in `2.4"s"` = `(2pi)/2.4=0.833pi"rad/s"`.

There are `360^0` swept in `2.4"s"` so there are `360/2.4=150` degrees swept per second.