If the period of an oscillatory motion is 2.4 seconds, what is the angular speed in rad/s and in degrees/s?

Sep 9, 2015

$0.833 \pi \text{rad/s}$

$150 \text{deg/s}$

Explanation:

There are $2 \pi$ radians in a circle.

The time period is the time taken to sweep $2 \pi$ radians.

So $2 \pi$ radians are swept in $2.4 \text{s}$ = $\frac{2 \pi}{2.4} = 0.833 \pi \text{rad/s}$.

There are ${360}^{0}$ swept in $2.4 \text{s}$ so there are $\frac{360}{2.4} = 150$ degrees swept per second.