# What is the period of oscillation of a mass of 40 kg on a spring with constant k = 10 N/m?

The answer is: $T = 12.56 s$
$T = 2 \pi \sqrt{\frac{m}{k}}$.
$T = 2 \cdot 3.14 \cdot \sqrt{\frac{40 k g}{10 \frac{N}{m}}} = 6.28 \cdot \sqrt{4 \frac{k g}{\frac{k g \cdot \frac{m}{s} ^ 2}{m}}} = 6.28 \cdot 2 s = 12.56 s$