Question

Question #717a6

Answer 1

You must use 9.9 mL of the `"NaOH"`.

Explanation:

You can use the dilution formula

`color(blue)(bar(ul(|color(white)(a/a)c_1V_1 = c_2V_2color(white)(a/a)|)))" "`

where `c_1` and `c_2` are the concentrations and `V_1` and `V_2` are the volumes.

You can rearrange this formula to get

`V_1 = V_2 × c_2/c_1`

Your data are:

`c_1 = "19 mol/L"; color(white)(ll)V_1 = "?"`
`c_2 = "0.15 mol/L"; V_2 = "1.25 L"`

`V_1 = "1.25 L" × (0.15 color(red)(cancel(color(black)("mol/L"))))/(19 color(red)(cancel(color(black)("mol/L")))) = "0.0099 L" = "9.9 mL"`