Question #717a6

1 Answer
May 28, 2017

Answer:

You must use 9.9 mL of the #"NaOH"#.

Explanation:

You can use the dilution formula

#color(blue)(bar(ul(|color(white)(a/a)c_1V_1 = c_2V_2color(white)(a/a)|)))" "#

where #c_1# and #c_2# are the concentrations and #V_1# and #V_2# are the volumes.

You can rearrange this formula to get

#V_1 = V_2 × c_2/c_1#

Your data are:

#c_1 = "19 mol/L"; color(white)(ll)V_1 = "?"#
#c_2 = "0.15 mol/L"; V_2 = "1.25 L"#

#V_1 = "1.25 L" × (0.15 color(red)(cancel(color(black)("mol/L"))))/(19 color(red)(cancel(color(black)("mol/L")))) = "0.0099 L" = "9.9 mL"#