Question

Question #f1c3c

Answer 1

Vertex is at `(-4,-21)`, y-intercept is at `(0,-5)`

Explanation:

`y=x^2+8x-5 or y=x^2+8x +16 -16-5 or (x+4)^2 -21`
Comparing with standard equation `y=a(x-h)^2 +k`
we get vertex as `h=-4 , k= -21 or (-4,-21)`

Putting `x=0` in the equation we get y intercept as `y= -5`
Vertex is at `(-4,-21)`, y-intercept is at `(0,-5)` graph{x^2+8x-5 [-80, 80, -40, 40]}[Ans]