Question #4536d

1 Answer
Douglas K.
Apr 7, 2017

#theta ~~ 230^@# or #theta ~~ 4" radians"#

Explanation:

We know that the angle must be in the Third Quadrant, because the signs of both of the components are negative, therefore, we must add #180^@# or #pi" radians"# to the inverse tangent function:

#theta = tan^-1(y/x)+180^@# or #theta = tan^-1(y/x)+pi" radians"#

#theta = tan^-1((-4)/-3)+180^@# or #theta = tan^-1((-4)/-3)+pi" radians"#

#theta ~~ 230^@# or #theta ~~ 4" radians"#

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