How do you find the length and direction of vector #2 - 4i#? Trigonometry Triangles and Vectors Component Vectors 1 Answer Harish Chandra Rajpoot Jul 3, 2018 Length of the vector #2-4i# #=\sqrt{2^2+(-4)^2}# #=2\sqrt5# And the angle #\theta# in CCW with the positive x-axis #\theta=-\tan^{-1}|-4/2|# #=-\tan^{-1}(2)# #=-63.435^\circ# Answer link Related questions What are component vectors? How do you use vector components to find the magnitude? How do you perform scalar multiplication with vectors? How do you find the resultant as a sum of two components? How do you use component vectors to solve real-world and applied problems? What would the representation of a vector that had three times the magnitude be if the vector... How do you calculate the unit vector? How do you find the magnitude of the horizontal and vertical components if the initial point is... How do you find the length and direction of vector #-4 - 3i#? What are the components of the vector between the origin an the polar coordinate #(6, pi/12)#? See all questions in Component Vectors Impact of this question 4765 views around the world You can reuse this answer Creative Commons License