# Question #0cf3d

Apr 13, 2017

92.6 grams

#### Explanation:

1 mol ${H}_{2} O$=18 grams =$\left(2 \times 1\right) + 16$
1 mol $M g {\left(O H\right)}_{2}$ = 24.3+34=58.3 grams.
It means to produce $3 \times 58.3 = 174.9$ grams of $M g {\left(O H\right)}_{2}$ you need $6 \times 18 = 108$ grams of water.
Since you want to produce 150 grams of magnesium hydroxide, you will need $\frac{150 \times 108}{174.9}$ grams of water. It is $92.6$ grams.