Question #0cf3d

1 Answer
G_Ozdilek
Apr 13, 2017

92.6 grams

Explanation:

Let's start with computing their molecular weights first:
1 mol #H_2O#=18 grams =#(2times1)+16#
1 mol #Mg(OH)_2# = 24.3+34=58.3 grams.

It means to produce #3times58.3=174.9# grams of #Mg(OH)_2# you need #6times18=108# grams of water.

Since you want to produce 150 grams of magnesium hydroxide, you will need #(150times108)/174.9# grams of water. It is #92.6# grams.

Related questions
See all questions in Stoichiometry
Impact of this question
2655 views around the world
You can reuse this answer
Creative Commons License