# What is the electronic configuration of Fe^(3+) ion?

Apr 22, 2017

Of the $\text{ferric ion..........?}$

#### Explanation:

For $\text{iron}$, $Z = 26$, and thus for elemental iron we have to distribute 26 electrons by the aufbau scheme, and for $F {e}^{3 +}$, we must distribute 23 electrons..................And so:

$1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 3 {d}^{5}$.

Note that a neutral iron atom has a configuration of.......

$1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{6}$ (26 electrons as required.) However, upon oxidation, the $4 s$ electrons are conceived to be removed FIRST, and this is typical for transition metal ions.

Would $F e \left(I I I\right)$ complexes be paramagnetic? Why or why not........?