Question

Question #3c8ff

Answer 1

The unhybridized p-orbital would contain 'zero' electrons.

Explanation:

C[He]2`s^2p_x^2p_y^0p_z^0` => ( C:[He]2`uarr/(sp^2)uarr/(sp^2)uarr/(sp^2)2(0/p_z))^+` + `e^-`

The carbocation will combine with 3H(`uarr/(1s)`)
=> `CH_3^+`[He]2((3`sigma)(1p_z^0))^+`

Image Credit: Stefan V. (May 31, 2015)