# Question #19845

May 1, 2017

The first step to solving such questions would be writing the chemical equations.

#### Explanation:

Given that there is $\text{5.85g}$ of calcium chloride, and that the molar mass of calcium chloride is

$40.08 + \left(2 \times 35.45\right) = {\text{110.98 gmol}}^{- 1}$

the amount of calcium chloride in moles is

$\text{5.85 g"/"110.98 gmol"^(-1) = "0.052712 moles}$

By molar ratio, the amount of sodium chloride formed in moles is $0.052712$ moles.

The molar mass of sodium chloride is

$22.99 + 35.45 = {\text{58.44 gmol}}^{- 1}$

The mass of sodium chloride formed is

$\text{0.052712 moles" xx "58.44 gmol"^(-1) = "3.08 g}$

${\text{mol" xx "gmol}}^{- 1}$