Question

Question #1b6aa

Answer 1

`-129 ^oC`

Explanation:

This question involves the pressure-temperature relationship of gases, and is illustrated by Gay-Lussac's law:

`(P_1)/(T_1) = (P_2)/(T_2)`

Remember that the temperature is the absolute temperature, so you have to convert the Celsius temperature to Kelvin:

`15 ^oC + 273 = 288 K`

We can rearrange this equation to solve for the final temperature, `T_2`:

`T_2 = (T_1)(P_2)/P_1`

Plug in known variables:

`T_2 = 288 K(225 mm Hg)/(450 mm Hg) = 144 K`

Finally, we convert the Kelvin temperature back to Celsius:

`144 K - 273 = -129 ^oC`