Question

Question #69eae

Answer 1

`"Dissociate............."`

Explanation:

The strength of an acid relates to the extent which the following equilibrium is completed:

`HX(aq) + H_2O(l) rightleftharpoonsH_3O^(+) + X^-`

For strong acids, `X^(-) =HSO_4^-, "halide" (X!=F), ClO_4^-`, the equilibrium lies STRONGLY to the right. For weaker acids, `HF, H_2SO_3, HO_2C-CH_3`, the equilibrium lies to the left.

And this we can use the equilibrium constant, `K_a`, as a determinant:

`K_a=([H_3O^+][X^-])/([HX])`

The given acids, have `K_a` values so large in water that the dissociation is considered to be quantitative.