# Under conditions of "NTP", what volume of SO_2(g) results from burning a 10*g mass of elemental sulfur?

May 19, 2017

We address the stoichiometric equation...........and I get a volume of under $10 \cdot L$...............

#### Explanation:

$S \left(s\right) + {O}_{2} \left(g\right) \rightarrow S {O}_{2} \left(g\right)$

Now depending on your definition of $\text{NTP}$ (they seem to change with the wind across syllabuses) we can work out the volume. I use values of $\text{NTP}$ to specify $P = 1 \cdot a t m$, and $T = 293.15 \cdot K$.

$\text{Moles of sulfur "-=" Moles of sulfur dioxide}$

$\text{Moles of sulfur} \equiv \frac{10 \cdot g}{32.06 \cdot g \cdot m o {l}^{-} 1} = 0.312 \cdot m o l$.

And thus there are $0.312 \cdot m o l$ $S {O}_{2}$ gas........given conversion stoichiometric conversion.

$V = \frac{n R T}{P} = \frac{0.312 \cdot m o l \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 293.15 \cdot K}{1 \cdot a t m}$

$= 7.5 \cdot L$