What mass of ammonia is required to give a #264*g# mass of #"ammonium sulfate"#?

1 Answer
Aug 2, 2017

Answer:

Approx. #68*g# of ammonia are required............

Explanation:

We need (i) a stoichiometric equation.......

#2NH_3(aq) + H_2SO_4(aq) rarr (NH_4)_2SO_4(aq)#

and (ii) equivalent quantities of #"ammonium sulfate"#

#"Moles of ammonium sulfate"=(264*g)/(132.14*g*mol^-1)=2*mol#.

And thus we need a #4*mol# quantity of ammonia (why #4 *mol#?).

And so...............

#"mass of ammonia"=4*molxx17.03*g*mol^-1=??*g#