What mass of ammonia is required to give a $264 \cdot g$ $264*g$ mass of $ammonium sulfate$ $"ammonium sulfate"$ ?

Question

What mass of ammonia is required to give a $264 \cdot g$ $264*g$ mass of $ammonium sulfate$ $"ammonium sulfate"$ ?

1 Answer

Impact of this question

1665 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-02T16:53:49

Approx. $68 \cdot g$ $68*g$ of ammonia are required............

Explanation:

We need (i) a stoichiometric equation.......

$2 N H_{3} (a q) + H_{2} S O_{4} (a q) \to {(N H_{4})}_{2} S O_{4} (a q)$ $2NH_3(aq) + H_2SO_4(aq) rarr (NH_4)_2SO_4(aq)$

and (ii) equivalent quantities of $ammonium sulfate$ $"ammonium sulfate"$

$Moles of ammonium sulfate = \frac{264 \cdot g}{132.14 \cdot g \cdot m o l^{- 1}} = 2 \cdot m o l$ $"Moles of ammonium sulfate"=(264*g)/(132.14*g*mol^-1)=2*mol$ .

And thus we need a $4 \cdot m o l$ $4*mol$ quantity of ammonia (why $4 \cdot m o l$ $4 *mol$ ?).

And so...............

$mass of ammonia = 4 \cdot m o l \times 17.03 \cdot g \cdot m o l^{- 1} = ? ? \cdot g$ $"mass of ammonia"=4*molxx17.03*g*mol^-1=??*g$

Science

Math

Humanities

... and beyond

What mass of ammonia is required to give a $264 \cdot g$ $264*g$ mass of $ammonium sulfate$ $"ammonium sulfate"$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What mass of ammonia is required to give a 264*g264⋅g264*g mass of "ammonium sulfate"ammonium sulfate"ammonium sulfate"?

1 Answer

Explanation:

Related questions

Impact of this question

What mass of ammonia is required to give a $264 \cdot g$ $264*g$ mass of $ammonium sulfate$ $"ammonium sulfate"$ ?