A #5*L# volume of gas exerts a pressure of #124*kPa#. How should volume evolve if pressure is increased to #206*kPa#?

1 Answer
Jun 10, 2017

Answer:

Well #P_1V_1=P_2V_2#....so #V_2=3.0*L#

Explanation:

Old #"Boyle's Law"# holds that for a given quantity gas, #Pprop1/V#, and thus #P=k/V#, where #k# is some (unspecified!) constant.

And if we solve for #k# under different conditions of pressure and volume (with temperature CONSTANT!), then.......

#V_2=(P_1xxV_1)/(P_2)=(5*Lxx124*kPa)/(206*kPa)=3.00*L#

Is this answer consistent with the parameters of the problem? Should volume DECREASE with INCREASED pressure?