# A 5*L volume of gas exerts a pressure of 124*kPa. How should volume evolve if pressure is increased to 206*kPa?

Jun 10, 2017

Well ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$....so ${V}_{2} = 3.0 \cdot L$

#### Explanation:

Old $\text{Boyle's Law}$ holds that for a given quantity gas, $P \propto \frac{1}{V}$, and thus $P = \frac{k}{V}$, where $k$ is some (unspecified!) constant.

And if we solve for $k$ under different conditions of pressure and volume (with temperature CONSTANT!), then.......

${V}_{2} = \frac{{P}_{1} \times {V}_{1}}{{P}_{2}} = \frac{5 \cdot L \times 124 \cdot k P a}{206 \cdot k P a} = 3.00 \cdot L$

Is this answer consistent with the parameters of the problem? Should volume DECREASE with INCREASED pressure?